12 In Craps
However, the math has to account for each die separately; hence, the probability of rolling a “7” in craps is 1 in 6. In declining order of probability, the possible combinations in craps are: 7 (1 in 6) 6 or 8 (5 in 36) 5 or 9 (4 in 36) 4 or 10 (3 in 36) 3 or 11 (2 in 36) 2 or 12 (1 in 36) 6. However, if the come out roll is 2,3 or 12 (craps) you lose. If any other number is rolled (4,5,6,8,9 or 10) it’s called the point. The shooter continues to throw the dice until he/she roles a 7 or the Point. If the point is rolled first, you win even money. What is the average number of rolls one would expect between a craps roll?ie. 2,3,12 to the next 2,3,12. I understand it could be 100 rolls im just looking for the mathematical average. I'm trying to work on something. A Come Out roll of 2, 3 or 12 (called Craps, the shooter is said to 'crap out') ends the round with players losing their Pass Line bets. A Come Out roll of 7 or 11 (a Natural) results in a win for Pass Line bets. The shooter continues to make Come Out rolls until he rolls 4, 5, 6, 8, 9, or 10, which number becomes the Point. Let's call x the expected number of rolls per shooter. The probability that any given round will end in one roll (with a 2, 3, 7, 11, or 12) is 1/3. If the player rolls a 4 or 10 on the come out roll the expected number of additional rolls is 4, because the probability of rolling a.